7 articles trouvés pour ce sujet.
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Matrice |
2006-02-01 |
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Kader pose la question : mon probleme est le suivant soit deux matrices carrees A et B d'ordre n qui sont anticommutatives AB= -BA , demontrer que au moins une des deux matrices n'est pas inversible si n est impair.
je n'arrive pas a utiliser le fait que n soit impair, trouver le rapport entre n impair et inverse des matrices, je pars sur la base de DETAB=DETA*DETB Claude Tardif lui répond. |
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4 by 4 determinants |
2008-06-27 |
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rav pose la question : How to solve problems of determinants which has four rows and four columns& please give me easy tips to solve permutations and combinations problems. Harley Weston lui répond. |
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Determinants |
2008-05-02 |
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Henry pose la question : I have a question about solving 3x3 matrices.
The traditional way, or at least the way I've been taught, is that if one has a 3x3 matrix such as:
[ a b c ]
[ d e f ]
[ g h i ]
one solves it according to this formula:
[ei - hf) - (bi - hc) + (bf - ec) = determinant.
According to a book I'm now studying to prepare for the California CSET exam, there is another, easier, way to solve it:
[ a b c ] [ a b ]
[ d e f ] [ d e ]
[ g h i ] [ g h ]
In other words, one repeats the first two rows of the matrix and adds them to the right.
At this point, the determinant is calculated thus:
(aei) +(bfg) + (cdh) - (gec) - (hfa) - (idb).
Is this, in fact, correct? Harley Weston lui répond. |
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Expanding determinants using minors |
2001-02-20 |
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A student pose la question : Question: 1) Determinants by expansion by minors. i) | 1 2 1 2 1 | | 1 0 0 1 0 | | 0 1 1 0 1 | | 1 1 2 2 1 | | 0 1 1 0 2 | Harley Weston lui répond. |
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order 4+ determinants |
1999-12-06 |
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Joe Kron pose la question : Why is it never shown how to calculate the value of 4x4 (or larger size) deteminants by the diagonal multiply methods that are generally shown for 2x2 and 3x3 determinants? The method I'm talking about is called Cramer's Rule??? Is this method not extensible to order 4+ and if not why not? Anyway the method always shown for order 4+ is called "reduction by minors" which is not the answer to this question. Walter Whiteley lui répond. |
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Area of a triangle from vertex coordinates |
1999-04-21 |
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Mark Tyler pose la question : I'm no schoolkid, but I liked your answers about triangles. You might enjoy a quick look at this, the kids may too. I was working on a Voronoi dual where I had to calculate the areas of very many triangles expressed as vertex coordinates, so I derived the following very direct formula: A = abs((x1-x2)*(y1-y3)-(y1-y2)*(x1-x3)) for triangle (x1,y1)(x2,y2)(x3,y3) I've never seen this in a textbook. Is it original? I doubt it, the proof is only a few lines long. Regardless, it may be fun for the kids, even if it's not on the curriculum. Walter Whitley lui répond. |
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Intersection of Planes |
1998-12-03 |
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Lindsay Fear pose la question : My name is Lindsay Fear. I am an OAC student (which is the Ontario equivalent to Grade 12 in most other states and provinces). I am in an Algebra and Geometry course and am currently studying a unit on equations of planes. Our teacher has given us this question that my friend and I have attempted several times, but we are still unable to solve it. My teacher has also suggested using the internet as a resource. The question is: Prove that a necessary condition that the three planes -x + ay + bz = 0 ax - y + cz = 0 bx + cy - z = 0 have a line in common is that a^2 + b^2 + c^2 + 2abc = 1 Walter Whiteley lui répond. |
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