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Associative or commutative? 2007-08-24
Terry pose la question :
5*(7*2)=(7*5)*2 Is this associative property or commutative ??? Both?
Penny Nom lui répond.
A frustum of a right pyramid 2007-08-24
Andrew pose la question :
Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5 in., whose upper base is a square with a side 3in., and whose altitude is 12 in. Round your answer to the nearest whole number.
A. 47cu in.     C. 226 cu in.
B. 196 cu in.     D. 1036 cu in.

Stephen la Rocque lui répond.
More on a percentage question 2007-08-23
Dee pose la question :
In a previous question, you answered:

"What percentage of $34.51 is $10.71?

I translate this English statement into a mathematical statement (equation) using the following

"what" is the unknown, call it x
"percent" is per-one-hundred, that is over 100
"of" is multiplication
"is" is the verb, which in an equation is the equal sign
Thus the English statement above becomes


x/100 $34.51 = $10.71

Solving for x yields

x = 31.03

Hence the gross profit is 31% of your selling price."

How did you solve for 'x'

Penny Nom lui répond.
Four fours 2007-08-23
Belinda pose la question :
My son came home with a math question that I can figure out. He needs to use only the number 4 and only four 4's, no less no more. The problems need the answers 11,13,14,and 18. He can use any mathematical sign except square root. He's been able to get all but these so far and I've worked them, but can't come up with the problems. Can anyone help?
Stephen la Rocque lui répond.
How many three button codes are possible? 2007-08-23
kim pose la question :
A home security device has ten buttons and is disarmed by pushing three buttons in sequence. How many three button codes are possible if each button can be pushed more than once in the code?
Stephen la Rocque lui répond.
Parametric equations 2007-08-22
will pose la question :
Graph and make a sketch of x = ysquared - 6y + 11 in parametric mode (hint: you need to come up with 2 parametric equations).

i have already figured out that the cartesian form of the parametrics will be y = +/- sqroot(x-2) + 3, but i do not know how to produce 2 parametric equations from this.

Penny Nom lui répond.
32,648 square footage = how much land? 2007-08-22
Elizabeth pose la question :
1. What amount of Land = an acre?
2. 32,648 square footage = how much land?

Penny Nom lui répond.
Which is more, 1.25 grams or 4.7 ml? 2007-08-22
jenni pose la question :
Which is more? 1.25 grams or 4.7 ml
Penny Nom lui répond.
65 grams =_____?mg 2007-08-22
Quan pose la question :
65 grams = _____?mg
Penny Nom lui répond.
Converting a repeating decimal to a common fraction 2007-08-22
isabelle pose la question :
how do you turn 6.333... into a fraction in simplest form?
Stephen La Rocque and Penny Nom lui répond.
Where do you use trigonometry? 2007-08-21
jenny pose la question :
where do you use trigonometry besides architecture and engineering?
Stephen La Rocque lui répond.
-31=6w-7 2007-08-21
Shaneka pose la question :
-31=6w-7
Penny Nom lui répond.
More on the sixth degree equation 2007-08-21
Farzan pose la question :
Equation 1 :
(R + (6.67*5.98*10^13/((R^2)*2)))^2 - (R^2) = (7.27*(10^-5)*R)^2
Equation 2 :
(6.67*5.98*10^13/(R^2*2))^2 + 6.67*5.98*10^13/R = (7.27*10^-5*R)^2
As you see if we expand the left part of the first equation and simplify, the equations become same, but these two equations have different answers in my math software.The first one has 3 amounts for R, but the second one has 6 amounts. Why are the answers different ?

Stephen La Rocque lui répond.
Two coplanar lines 2007-08-21
Robin pose la question :
I am going two show that the two lines are coplanar:

(x-5)/4=(y-7)/4=-(z+3)/5
(x-8)/7=y-4=(z-5)/3

I know I have to find a point that lie on both lines, but dont really get it.

Stephen La Rocque and Penny Nom lui répond.
Ten workers perform one job in five days 2007-08-21
Kenneth pose la question :
If ten workers perform one job in 5 days, one person performs one job in how many days?

Here is the calculation that I used:
(10 workers X 1 job X 5 days)/(1 person X 1 job X ? days)

The above equals 50/1, and the answer is 50 days because 50/1 = 50. In this calculation I can determine any number of workers or days if the number of jobs remains the same as that in the group of factors from the numerator (10 workers X 1 job X 5 days), that is 1 job. Here is another example to help clarify: (10 workers X 1 job X 5 days)/(? workers X 1 job X 10 days) This equals 50/10. The answer is 5 workers. So, if 10 workers can perform 1 job in 5 days, 5 workers can perform 1 job in 10 days.

Now, if I replace "1 job" from (10 workers X 1 job X 5 days) with a different number, for example, 4 jobs, this amount will prevent the calculation from producing the correct answer.

Here is an example: (10 workers X 1 job X 5 days)/(10 workers X 4 jobs X ? days) Mathematically, the calculation works, but the answer, 1.25 days, is not correct, if I'm not mistaken. If 10 workers can perform 1 job in 5 days, they cannot, by working at the same rate, perform 4 jobs in 1.25 days.

Can you explain, with a simple explanation, why the number representing the jobs in this calculation needs to be the same in the group of factors in both the numerator and in the denominator in order to provide the correct answer?

Harley Weston lui répond.
 
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