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2 articles trouvés pour ce sujet.
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More on the sixth degree equation |
2007-08-21 |
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Farzan pose la question :
Equation 1 :
(R + (6.67*5.98*10^13/((R^2)*2)))^2 - (R^2) = (7.27*(10^-5)*R)^2
Equation 2 :
(6.67*5.98*10^13/(R^2*2))^2 + 6.67*5.98*10^13/R = (7.27*10^-5*R)^2
As you see if we expand the left part of the first equation and simplify, the
equations become same, but these two equations have different answers in my
math software.The first one has 3 amounts for R, but the second one has 6
amounts. Why are the answers different ?
Stephen La Rocque lui répond. |
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A sixth degree equation |
2007-08-20 |
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Farzan pose la question :
Dear friends
I need to solve this equation with an understandable method for high-school students :
(6.67*5.98*10^13/(R^2*2))^2 + 6.67*5.98*10^13/R = (7.27*10^-5*R)^2
please solve this problem if you have time.
Harley Weston lui répond. |
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