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Lucas' theorem |
2001-10-09 |
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Tania pose la question : How could I demonstrate: nCp is congruent to floor(n/p) (modulo p)? where rCk is a binomial coefficient, rCk = r(r-1)...(r-k+1)/k(k-1)...1, and p is a prime number Richard McIntosh lui répond. |
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