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antiderivative

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9 articles trouvés pour ce sujet.
 
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Distance as a function of acceleration 2013-07-10
Tom pose la question :
If you start at a stoplight and your acceleration is 16t - t^2, how far have you gone after 8 seconds?
Penny Nom lui répond.
Integral 1/(25-x^2)^3/2 2012-02-22
John pose la question :
Integral 1/(25-x^2)^3/2
Harley Weston lui répond.
An antiderivative of the square root of (8t + 3) 2011-04-19
Caitlyn pose la question :
I know how to take an antiderivative. But this one's stumping me. I need it to finish a problem. What's the antiderivative of the square root of (8t + 3)

~Caitlyn=

Penny Nom lui répond.
The integral of (x^2*exp(x)/(exp(x)-1)^2 2010-08-09
sujoy pose la question :
please find this integral for me

int(x^2*exp(x)/(exp(x)-1)^2

Robert Dawson lui répond.
An antiderivative problem 2009-08-13
Indrajit pose la question :
∫4e^x + 6e^-x/(9e^x + 4e^-x)dx = Ax + Bloge(9e2x - 4) + C

then A=?......B=?.....C=?

plz solve it...."^" stands for "to the power of"....

Harley Weston lui répond.
A definite integral 2009-02-09
Mathata pose la question :
Evaluate: integral from 0 to 1, x^2 e^x^3dx
Harley Weston lui répond.
Antiderivative of 1/(x(1 - x)) 2008-10-22
Matt pose la question :
derivative of dx/(x(1-x))

From what I've seen I should break apart the equation as such derivative of dx/x - dx/(1-x) and then get the 2 corresponding log functions.

If that is correct why does this factoring work, if that is incorrect what is the proper way to find the derivative.

Harley Weston lui répond.
f(x+y) = f(x) + f(y) + 2xy 2007-11-01
Marcia pose la question :
For all real numbers x and y, let f be a function such that f(x+y) = f(x) + f(y) + 2xy and such that the limit as h -> 0 of f(h) / h = 7, find: f(0), use the definition of the derivative to find f'(x), and find f(x).
Penny Nom lui répond.
Velocity and acceleration 2005-10-27
Candace pose la question :
When taking the integral of the position function, you get the velocity function, and the same for velocity to acceleration. So when you do each of these, you get a function. But when you integrate on a graph, you get an area under a curve. The area is un units squared- where do the units go when you make it an equation? How can a function be an area?
Harley Weston lui répond.
 
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