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Un article trouvé pour ce sujet.
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A geometry problem |
2007-08-20 |
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samhita pose la question :
ABC is a triangle. Let D be a point on side BC produced beyond B such that BD=BA. Let M be the mid-point of AC. The bisector of angle ABC meets DM at P. Prove that angle BAP=angle ACB.
Chris Fisher lui répond. |
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