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Un article trouvé pour ce sujet.
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The square root of 6 is irrational |
2017-10-02 |
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John pose la question :
http://mathcentral.uregina.ca/QQ/database/QQ.09.06/sylvia1.html
In the initial assumption of that proof, root 6 is assumed to be a/b where a and b have no common factors, but why does having a common factor make it irrational?
Penny Nom lui répond. |
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