15 articles trouvés pour ce sujet.
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   | Divisibility of 3n^5+7n | 2016-12-14 | 
  |  | Parag pose la question : 
 Question from Parag, a student: if n is a natural number,then 3n^5+7n is divisible bya)2
 b)3
 c)5
 d)7
 i got the answer but still i need a valid alternate approach. Penny Nom lui répond.
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   | 4821x14y is an 8-digit number divisible by 72 | 2014-08-06 | 
  |  | RAYA pose la question : if 4821x14y is an 8-digit number divisible by 72. How many values can x and y take?
 Penny Nom lui répond.
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   | The square of any odd number, decreased by 1, is divisible by 8 | 2012-11-16 | 
  |  | bailey pose la question : Prove that the square of any odd number, decreased by 1, is divisible by 8
 Penny Nom lui répond.
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   | The difference of the two numbers | 2010-02-15 | 
  |  | Steve pose la question : The difference of the two numbers 'abcdef ' and ' fdebca ' is divisible by 271. prove
that b = d and c = e.
 Claude Tardif lui répond.
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   | How many combinations of 8614 are divisible by 7? | 2008-01-22 | 
  |  | Rebecca pose la question : How many combinations of 8614 are divisible  by 7 equally (with no remainder)?
 Penny Nom lui répond.
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   | Induction - divisibility | 2007-08-04 | 
  |  | Jerry pose la question : How would you prove that for any positive integer n, the value of the expression 3^(2n+2) - 8n -9 is divisible by 64.
 Chris Fisher and Penny Nom lui répond.
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   | Divisibility | 2007-05-18 | 
  |  | Ashish pose la question : A number is divisible by 2^n if the last n digits of the number are divisible by 2^n.
Why?
 Penny Nom and Claude Tardif lui répond.
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   | Divisibility by each of the first ten counting numbers | 2005-10-17 | 
  |  | Simon pose la question : determine smallest positive integer that is divisible by each of the first ten counting numbers
 Penny Nom lui répond.
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   | A 3 digit number divisible by 7 | 2004-05-03 | 
  |  | A student pose la question : We need to arrange 1,3 and 6 to form a 3 digit number that is divisible by 7.
 Penny Nom lui répond.
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   | Divisibility by 2 or 5 or both | 2003-10-30 | 
  |  | Abdu pose la question : How many positive integers less than 1,001 are divisible by either 2 or 5 or both?
 Penny Nom lui répond.
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   | Three consecutive positive intergers | 2003-02-09 | 
  |  | Yew pose la question : Prove that when we multiply any consecutive positive intergers, the result is always divisible by 6.
 
 ex. (7)(8)(9) = 504 = 6 (84)
 Penny Nom lui répond.
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   | Divisibility of 5 2002 | 2002-08-25 | 
  |  | Simon pose la question : I need to ask you a question if 5 2002 and 3 2002 are divisible by 26.
 Penny Nom lui répond.
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   | Divisibility by 9 | 2000-10-24 | 
  |  | Kelera pose la question : If the sum of the digits of a number is divisible by 9, then the number itself it divisible by 9. Why is that? How do you explain this?
 Penny Nom lui répond.
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   | 111...1222...2 | 1999-08-11 | 
  |  | Brad Goorman pose la question : Let N = 111...1222...2, where there are 1999 digits of 1 followed by 1999 digits of 2.
 Express N as the product of four integers,  each of them greater than 1.
 Penny Nom lui répond.
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   | Divisibility of 2n choose n. | 1996-09-24 | 
  |  | Kathy Doan pose la question : Can you prove that "2n choose n" is not divisible by 3, 5, and 7 for infinitely many n?
 Penny Nom lui répond.
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