13 articles trouvés pour ce sujet.
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Golf for 28 golfers over 4 days |
2020-11-14 |
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David pose la question : hi, I was wondering if you could help me with a golf draw, I have 28 players and wish to play a four round foursomes over 4 days
I would like to minimize the amount of games that they play together. Harley Weston lui répond. |
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20 golfers for 6 days |
2015-09-11 |
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Dave pose la question : have 20 golfers for 6 days. Each player should pair with 18 golfers
used a system on your website which is good for 5 days, but cannot get the 6th day.
Thanks for your help Dave Victoria West lui répond. |
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On what day of the week did 1994 begin? |
2015-04-05 |
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tayyaba pose la question : there were 365 days in the year 1993
the first day of the year was friday.
on what day of the week did 1994 begin? Penny Nom lui répond. |
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13 golfers in groupings of 4, 3, 3 and 3 |
2014-03-26 |
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Lennart pose la question : How can I organise 13 players playing in groupings of 4,3,3,3 for 3 rounds of golf in a way that all play with all others but a minimum of times with the same players(?)If possible, nobody should play in the 4 ball more than once. I would be grateful for an answer/proposal! Thank you, LR Victoria West lui répond. |
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8 golfers playing 8 games |
2013-07-03 |
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Johan pose la question : We have 8 golfers playing 8 games, and we want to schedule them so that they play together equal amount of times, or as close as you can get to that.
They will be playing in two four balls each day.
Anyone sorted this one out yet, I will really appreciate a solution?
Thanks
Johan Victoria West lui répond. |
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The 10000th day of her life |
2012-02-21 |
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derrick pose la question : Ella was born early in the morning on a Friday.She got married on the 10000th day of her life. What day of the week was it? Penny Nom lui répond. |
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Mathematics and a musical dilemma |
2011-01-19 |
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rahul pose la question : how is mathematics applied in entertainment? Harley Weston lui répond. |
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Probability and birthdays |
2009-01-22 |
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La pose la question : Neglecting the effect of leap years, what is the chance that, of 6 people selected at random, 2 will have the same birthday? Penny Nom lui répond. |
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26 paychecks |
2009-01-21 |
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Kenneth pose la question : Hello:
If someone is paid every two weeks, he receives 26 paychecks per year, (52 weeks/year)divided by (2 weeks/1 check) equals 26 paychecks per year.
However, if the calculation uses days instead of weeks, the answer is not exactly 26 paychecks. For example, 365 days divided by 14 days per paycheck
equals 26 1/14 paychecks. Fourteen days is equivalent to two weeks, isn't it?
Why is there this fractional amount of 1/14 of a paycheck? Robert Dawson and Victoria West lui répond. |
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What year were the girls born in? |
2008-01-06 |
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Nyra pose la question : Christmas 2004 was over and three teenagers were looking forward to their birthdays. Eric's was in February and Lisa's and Tammy's in January. Tammy is 8 weeks older than Eric, but 3 days younger than Lisa. What year were the girls born in? Claude Tardif lui répond. |
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Ten workers perform one job in five days |
2007-08-21 |
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Kenneth pose la question : If ten workers perform one job in 5 days, one person performs one job in how many days?
Here is the calculation that I used:
(10 workers X 1 job X 5 days)/(1 person X 1 job X ? days)
The above equals 50/1, and the answer is 50 days because 50/1 = 50. In this calculation I can determine any number of workers or days if the number of jobs remains the same as that in the group of factors from the numerator (10 workers X 1 job X 5 days), that is 1 job. Here is another example to help clarify: (10 workers X 1 job X 5 days)/(? workers X 1 job X 10 days) This equals 50/10. The answer is 5 workers. So, if 10 workers can perform 1 job in 5 days, 5 workers can perform 1 job in 10 days.
Now, if I replace "1 job" from (10 workers X 1 job X 5 days) with a different number, for example, 4 jobs, this amount will prevent the calculation from producing the correct answer.
Here is an example: (10 workers X 1 job X 5 days)/(10 workers X 4 jobs X ? days) Mathematically, the calculation works, but the answer, 1.25 days, is not correct, if I'm not mistaken. If 10 workers can perform 1 job in 5 days, they cannot, by working at the same rate, perform 4 jobs in 1.25 days.
Can you explain, with a simple explanation, why the number representing the jobs in this calculation needs to be the same in the group of factors in both the numerator and in the denominator in order to provide the correct answer? Harley Weston lui répond. |
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Your birthdays until your one hundredth |
2006-09-09 |
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Alan pose la question : which of your birthdays until your one hundredth, fall on the same day of the week as the day you were born? Chris Fisher lui répond. |
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2^9833 days from today |
2004-12-26 |
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Pauline pose la question : Today is Monday, 1 October 2001. What day of the week will be 29833 days from today? Penny Nom lui répond. |
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